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Chapter 4 · Sampling · Slide 148/274

Correction for a small population: ± 1 %

Calculations show approximate values for a 95% confidence level

4.4 · Sample Size Correction in Practice

Correction for a small population: ± 1 %


n ≈ (1/E)² ncorr=n · Nn + N − 1
Computationally required
n = (1 / 0.01)² = 100²
10.000
… with only N = 100 elements in the population.
Corrected
ncorr = (10.000 · 100) / (10.000 + 100 − 1)
= 1.000.000 / 10.099
≈ 99

Calculations show approximate values for a 95% confidence level

QUESTIONSTAR · Dr. Paul Marx 148 / 274
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